correct bench name
Vladimir Bauer
5 years ago
cwriter/clear_lines_bench_test.go
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package cwriter
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import (
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"bytes"
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"fmt"
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"io/ioutil"
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"strconv"
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"testing"
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)
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func BenchmarkWithFprintf(b *testing.B) {
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cuuAndEd := "\x1b[%dA\x1b[J"
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for i := 0; i < b.N; i++ {
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fmt.Fprintf(ioutil.Discard, cuuAndEd, 4)
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}
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}
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func BenchmarkWithJoin(b *testing.B) {
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bCuuAndEd := [][]byte{[]byte("\x1b["), []byte("A\x1b[J")}
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for i := 0; i < b.N; i++ {
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ioutil.Discard.Write(bytes.Join(bCuuAndEd, []byte(strconv.Itoa(4))))
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}
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}
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func BenchmarkWithAppend(b *testing.B) {
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escOpen := []byte("\x1b[")
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cuuAndEd := []byte("A\x1b[J")
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for i := 0; i < b.N; i++ {
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ioutil.Discard.Write(append(strconv.AppendInt(escOpen, 4, 10), cuuAndEd...))
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}
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}
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func BenchmarkWithCopy(b *testing.B) {
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w := New(ioutil.Discard)
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w.lineCount = 4
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for i := 0; i < b.N; i++ {
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w.ansiCuuAndEd()
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}
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}
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package cwriter
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import (
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"bytes"
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"fmt"
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"io/ioutil"
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"strconv"
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"testing"
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)
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func BenchmarkWithFprintf(b *testing.B) {
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cuuAndEd := "\x1b[%dA\x1b[J"
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for i := 0; i < b.N; i++ {
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fmt.Fprintf(ioutil.Discard, cuuAndEd, 4)
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}
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}
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func BenchmarkWithJoin(b *testing.B) {
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bCuuAndEd := [][]byte{[]byte("\x1b["), []byte("A\x1b[J")}
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for i := 0; i < b.N; i++ {
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ioutil.Discard.Write(bytes.Join(bCuuAndEd, []byte(strconv.Itoa(4))))
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}
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}
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func BenchmarkWithAppend(b *testing.B) {
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escOpen := []byte("\x1b[")
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cuuAndEd := []byte("A\x1b[J")
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for i := 0; i < b.N; i++ {
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ioutil.Discard.Write(append(strconv.AppendInt(escOpen, 4, 10), cuuAndEd...))
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}
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}
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func BenchmarkWithCopy(b *testing.B) {
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w := New(ioutil.Discard)
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w.lineCount = 4
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for i := 0; i < b.N; i++ {
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w.ansiCuuAndEd()
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}
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}
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